Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 03:29Z

e^{i\pi} + 1 = 0

Fe₂O₃ + 3CO → 2Fe + 3CO₂

460K

\binom{n}{k} = \frac{n!}{k!(n-k)!}

438K

F = ma

E = mc²

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det| 7 4 ; 4 8 | = 40

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12θ² + 8θ + 3 = 0

F = G m₁m₂ / r²

448K

E = mc²

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ω = 2πf

∑_{k=1}^{n} k = n(n+1)/2

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∇ × E = −∂B/∂t

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N₂ + 3H₂ ⇌ 2NH₃

∂β/∂β = 6β

181K

6ω² + 4ω + 4 = 0

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C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

∑_{k=1}^{n} k = n(n+1)/2

359K

\lim_{r\to 0} \frac{\sin r}{r} = 1

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9x² + 4x + 5 = 0