Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:09Z

11n² + 5n + 4 = 0

∂x/∂ψ = 6x

460K

\lim_{ω\to 0} \frac{\sin ω}{ω} = 1

438K

∫₀^∞ e^(-x²) dx = √π / 2

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

186K

F = G m₁m₂ / r²

411K

4φ² + 6φ + 2 = 0

∇²r = 0

448K

∇ × E = −∂B/∂t

22K

∫₀^∞ e^(-φ²) dφ = √π / 2

det| 5 9 ; 7 6 | = -33

459K

CaCO₃ → CaO + CO₂

406K

∇²ω = 0

∇²t = 0

181K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

80K

d/dr [r^2] = 2r^1

det| 5 6 ; 2 6 | = 18

359K

det| 7 4 ; 4 8 | = 40

455K