Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-19 18:06Z

e^{i\pi} + 1 = 0

det| 5 3 ; 7 6 | = 9

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PV = nRT

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λ = h/p

∑_{k=1}^{n} k = n(n+1)/2

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det| 9 4 ; 1 10 | = 86

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det| 6 7 ; 7 7 | = -7

∇ × E = −∂B/∂t

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d/dt [t^3] = 3t^2

411K

∇²ψ = 0

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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\lim_{ω\to 0} \frac{\sin ω}{ω} = 1

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10t² + 9t + 5 = 0

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