Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-20 04:47Z

∇²n = 0

E = mc²

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∫₀^∞ e^(-x²) dx = √π / 2

263K

9r² + 4r + 1 = 0

∇²t = 0

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det| 7 4 ; 4 8 | = 40

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

∑_{k=1}^{n} k = n(n+1)/2

333K

\frac{4}{9} \sum_{i=1}^{n} i^{2}

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11γ² + 3γ + 6 = 0

\lim_{t\to 0} \frac{\sin t}{t} = 1

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det| 7 6 ; 1 8 | = 50

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iħ ∂ψ/∂t = Ĥψ

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N₂ + 3H₂ ⇌ 2NH₃

128K