Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-20 01:05Z

12γ² + 2γ + 2 = 0

d/dt [t^3] = 3t^2

273K

∇ × E = −∂B/∂t

263K

∑_{k=1}^{n} k = n(n+1)/2

N₂ + 3H₂ ⇌ 2NH₃

139K

det| 9 5 ; 1 10 | = 85

108K

5φ² + 3φ + 0 = 0

∇²ω = 0

333K

8θ² + 8θ + 6 = 0

160K

ΔS ≥ 0

iħ ∂ψ/∂t = Ĥψ

439K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

413K

∫₀^∞ e^(-y²) dy = √π / 2

8ψ² + 7ψ + 0 = 0

297K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

Fe₂O₃ + 3CO → 2Fe + 3CO₂

N₂ + 3H₂ ⇌ 2NH₃