Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 14:33Z

3γ² + 8γ + 4 = 0

∂γ/∂θ = 2γ

460K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

438K

PV = nRT

\lim_{t\to 0} \frac{\sin t}{t} = 1

186K

d/dt [t^3] = 3t^2

411K

det| 1 9 ; 5 2 | = -43

7γ² + 8γ + 3 = 0

448K

ω = 2πf

22K

ω = 2πf

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

459K

6x² + 6x + 1 = 0

406K

∇ × E = −∂B/∂t

181K

∑_{k=1}^{n} k = n(n+1)/2

80K

8ψ² + 7ψ + 0 = 0

359K