Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 14:23Z

3γ² + 8γ + 4 = 0

6x² + 6x + 1 = 0

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∇ × E = −∂B/∂t

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PV = nRT

∑_{k=1}^{n} k = n(n+1)/2

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\binom{n}{k} = \frac{n!}{k!(n-k)!}

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det| 1 9 ; 5 2 | = -43

12y² + 5y + 7 = 0

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\binom{n}{k} = \frac{n!}{k!(n-k)!}

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ω = 2πf

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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∂y/∂γ = 8y

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∂n/∂ψ = 6n

8ψ² + 7ψ + 0 = 0

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N₂ + 3H₂ ⇌ 2NH₃

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N₂ + 3H₂ ⇌ 2NH₃

iħ ∂ψ/∂t = Ĥψ

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ω = 2πf

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\binom{n}{k} = \frac{n!}{k!(n-k)!}