Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 11:38Z

∇²t = 0

PV = nRT

460K

∑_{k=1}^{n} k = n(n+1)/2

438K

det| 6 4 ; 3 7 | = 30

C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

186K

∇ × E = −∂B/∂t

411K

ΔS ≥ 0

det| 9 4 ; 1 10 | = 86

448K

d/dt [t^3] = 3t^2

22K

1z² + 3z + 2 = 0

det| 5 3 ; 7 6 | = 9

459K

6n² + 7n + 6 = 0

406K

7t² + 3t + 1 = 0

det| 11 5 ; 2 12 | = 122

det| 8 3 ; 4 9 | = 60