Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 11:43Z

∇²t = 0

det| 7 4 ; 4 8 | = 40

460K

E = mc²

438K

det| 6 4 ; 3 7 | = 30

∇ × E = −∂B/∂t

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∂β/∂β = 6β

411K

ΔS ≥ 0

7r² + 8r + 5 = 0

448K

F = G m₁m₂ / r²

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1z² + 3z + 2 = 0

∑_{k=1}^{n} k = n(n+1)/2

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CH₄ + 2O₂ → CO₂ + 2H₂O

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7t² + 3t + 1 = 0

9θ² + 7θ + 4 = 0

181K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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det| 8 3 ; 4 9 | = 60

\binom{n}{k} = \frac{n!}{k!(n-k)!}

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