Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 23:04Z

11t² + 8t + 0 = 0

∑_{k=1}^{n} k = n(n+1)/2

460K

∫₀^∞ e^(-θ²) dθ = √π / 2

438K

∂ω/∂β = 7ω

det| 7 4 ; 4 8 | = 40

186K

∇ × E = −∂B/∂t

411K

det| 3 3 ; 7 4 | = -9

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

448K

\lim_{t\to 0} \frac{\sin t}{t} = 1

22K

PV = nRT

∇²ω = 0

459K

N₂ + 3H₂ ⇌ 2NH₃

406K

det| 3 6 ; 0 4 | = 12

181K