Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-18 16:20Z
10γ² + 4γ + 3 = 0
∑_{k=1}^{n} k = n(n+1)/2
438K
d/dβ [β^11] = 11β^10
3x² + 4x + 6 = 0
det| 7 4 ; 4 8 | = 40
448K
det| 1 4 ; 3 2 | = -10
406K
det| 3 1 ; 7 4 | = 5
181K
∑_{k=1}^{n} k = n(n+1)/2
80K