Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 19:49Z

CH₄ + 2O₂ → CO₂ + 2H₂O

∇²ω = 0

460K

8ψ² + 7ψ + 0 = 0

438K

det| 1 1 ; 4 2 | = -2

det| 3 6 ; 0 4 | = 12

186K

iħ ∂ψ/∂t = Ĥψ

411K

CaCO₃ → CaO + CO₂

∇ × E = −∂B/∂t

448K

F = G m₁m₂ / r²

22K

det| 8 4 ; 2 9 | = 64

∇ × E = −∂B/∂t

459K

9θ² + 7θ + 4 = 0

406K

4n² + 8n + 6 = 0

\lim_{t\to 0} \frac{\sin t}{t} = 1

181K

d/dt [t^3] = 3t^2

80K

6α² + 1α + 5 = 0

\oint_C \vec{F}\cdot d\vec{r} = 0

CH₄ + 2O₂ → CO₂ + 2H₂O

∫₀^∞ e^(-ω²) dω = √π / 2