Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 12:41Z

∑_{k=1}^{n} k = n(n+1)/2

F = G m₁m₂ / r²

460K

e^{i\pi} + 1 = 0

438K

4y² + 7y + 7 = 0

N₂ + 3H₂ ⇌ 2NH₃

186K

N₂ + 3H₂ ⇌ 2NH₃

411K

∇²t = 0

8γ² + 1γ + 1 = 0

448K

N₂ + 3H₂ ⇌ 2NH₃

22K

6β² + 2β + 2 = 0

∂γ/∂θ = 2γ

459K

∑_{k=1}^{n} k = n(n+1)/2

406K

2φ² + 2φ + 5 = 0

iħ ∂ψ/∂t = Ĥψ

181K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

80K

\lim_{n\to 0} \frac{\sin n}{n} = 1

det| 7 4 ; 4 8 | = 40

359K

det| 7 8 ; 0 8 | = 56