Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-18 11:38Z
∇²t = 0
det| 6 4 ; 3 7 | = 30
CH₄ + 2O₂ → CO₂ + 2H₂O
411K
ΔS ≥ 0
∫₀^∞ e^(-t²) dt = √π / 2
448K
∑_{k=1}^{n} k = n(n+1)/2
22K
1z² + 3z + 2 = 0
det| 7 4 ; 4 8 | = 40
459K
7t² + 3t + 1 = 0
det| 4 7 ; 2 5 | = 6
181K
∑_{k=1}^{n} k = n(n+1)/2
80K