Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:01Z

11n² + 5n + 4 = 0

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

460K

F = G m₁m₂ / r²

438K

∫₀^∞ e^(-x²) dx = √π / 2

∇²n = 0

186K

\frac{4}{6} \sum_{i=1}^{n} i^{2}

411K

4φ² + 6φ + 2 = 0

∇²β = 0

448K

\frac{8}{7} \sum_{i=1}^{n} i^{2}

22K

∫₀^∞ e^(-φ²) dφ = √π / 2

det| 2 6 ; 0 3 | = 6

459K

det| 9 4 ; 1 10 | = 86

406K

∇²ω = 0

d/dx [x^3] = 3x^2

181K

iħ ∂ψ/∂t = Ĥψ

80K

d/dr [r^2] = 2r^1

N₂ + 3H₂ ⇌ 2NH₃

359K

ΔS ≥ 0

8β² + 5β + 0 = 0

det| 12 6 ; 6 13 | = 120