Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 11:40Z

∇²t = 0

CH₄ + 2O₂ → CO₂ + 2H₂O

460K

∑_{k=1}^{n} k = n(n+1)/2

438K

det| 6 4 ; 3 7 | = 30

N₂ + 3H₂ ⇌ 2NH₃

186K

N₂ + 3H₂ ⇌ 2NH₃

411K

ΔS ≥ 0

∇ × E = −∂B/∂t

448K

iħ ∂ψ/∂t = Ĥψ

22K

1z² + 3z + 2 = 0

\lim_{t\to 0} \frac{\sin t}{t} = 1

459K

8ψ² + 7ψ + 0 = 0

406K

7t² + 3t + 1 = 0

∂γ/∂θ = 2γ

181K

det| 11 5 ; 2 12 | = 122

det| 8 3 ; 4 9 | = 60

10γ² + 8γ + 2 = 0

∇ × E = −∂B/∂t

λ = h/p