Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-18 14:43Z
3γ² + 8γ + 4 = 0
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
438K
PV = nRT
∑_{k=1}^{n} k = n(n+1)/2
186K
det| 1 9 ; 5 2 | = -43
det| 3 6 ; 0 4 | = 12
448K
∑_{k=1}^{n} k = n(n+1)/2
22K
ω = 2πf
det| 7 4 ; 4 8 | = 40
406K
∂n/∂ψ = 6n
∫₀^∞ e^(-ψ²) dψ = √π / 2
N₂ + 3H₂ ⇌ 2NH₃