Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-19 20:21Z

∑_{k=1}^{n} k = n(n+1)/2

E = mc²

451K

E = mc²

264K

det| 8 9 ; 3 9 | = 45

∇²ω = 0

297K

det| 7 2 ; 7 8 | = 42

252K

C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

8ψ² + 7ψ + 0 = 0

48K

∑_{k=1}^{n} k = n(n+1)/2

411K

∑_{k=1}^{n} k = n(n+1)/2

377K

\frac{4}{9} \sum_{i=1}^{n} i^{2}

299K

\frac{2}{2} \sum_{i=1}^{n} i^{2}

401K

∇ × E = −∂B/∂t

420K

d/dt [t^3] = 3t^2

109K