Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 14:22Z

3γ² + 8γ + 4 = 0

\lim_{ω\to 0} \frac{\sin ω}{ω} = 1

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8ψ² + 7ψ + 0 = 0

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PV = nRT

N₂ + 3H₂ ⇌ 2NH₃

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∑_{k=1}^{n} k = n(n+1)/2

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det| 1 9 ; 5 2 | = -43

iħ ∂ψ/∂t = Ĥψ

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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4t² + 3t + 3 = 0

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7r² + 8r + 5 = 0

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∫₀^∞ e^(-θ²) dθ = √π / 2

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C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

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∇²ω = 0

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