Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:27Z

11n² + 5n + 4 = 0

\lim_{ω\to 0} \frac{\sin ω}{ω} = 1

460K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

438K

∫₀^∞ e^(-x²) dx = √π / 2

e^{i\pi} + 1 = 0

186K

e^{i\pi} + 1 = 0

411K

4φ² + 6φ + 2 = 0

10t² + 9t + 5 = 0

448K

F = G m₁m₂ / r²

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∫₀^∞ e^(-φ²) dφ = √π / 2

det| 11 5 ; 0 12 | = 132

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ΔS ≥ 0

406K

∇²ω = 0

iħ ∂ψ/∂t = Ĥψ

181K

F = G m₁m₂ / r²

80K

det| 9 4 ; 1 10 | = 86

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CH₄ + 2O₂ → CO₂ + 2H₂O

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