Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-18 02:50Z
det| 5 4 ; 6 6 | = 6
det| 4 7 ; 2 5 | = 6
438K
∇²φ = 0
det| 9 4 ; 1 10 | = 86
186K
det| 12 5 ; 4 13 | = 136
det| 11 5 ; 0 12 | = 132
448K
∑_{k=1}^{n} k = n(n+1)/2
CaCO₃ → CaO + CO₂
E = mc²
ω = 2πf
CH₄ + 2O₂ → CO₂ + 2H₂O