Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-18 15:12Z
11n² + 5n + 4 = 0
∫₀^∞ e^(-x²) dx = √π / 2
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
186K
∑_{k=1}^{n} k = n(n+1)/2
411K
4φ² + 6φ + 2 = 0
det| 9 4 ; 1 10 | = 86
22K
∫₀^∞ e^(-φ²) dφ = √π / 2
∑_{k=1}^{n} k = n(n+1)/2
459K
∇²ω = 0
∑_{k=1}^{n} k = n(n+1)/2
181K
det| 2 3 ; 5 3 | = -9
80K
d/dr [r^2] = 2r^1
ΔS ≥ 0