Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-20 04:34Z

∇²n = 0

∇ × E = −∂B/∂t

273K

∫₀^∞ e^(-t²) dt = √π / 2

263K

9r² + 4r + 1 = 0

\oint_C \vec{F}\cdot d\vec{r} = 0

139K

det| 7 4 ; 4 8 | = 40

108K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

F = ma

333K

F = G m₁m₂ / r²

160K

11γ² + 3γ + 6 = 0

C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

439K

∇²γ = 0

413K

\lim_{ψ\to 0} \frac{\sin ψ}{ψ} = 1

det| 12 6 ; 6 13 | = 120

det| 6 1 ; 3 7 | = 39

e^{i\pi} + 1 = 0