Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-19 20:24Z

∑_{k=1}^{n} k = n(n+1)/2

∑_{k=1}^{n} k = n(n+1)/2

451K

det| 7 4 ; 4 8 | = 40

264K

det| 8 9 ; 3 9 | = 45

PV = nRT

297K

N₂ + 3H₂ ⇌ 2NH₃

252K

C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

d/dφ [φ^1] = 1φ^0

48K

det| 3 7 ; 2 4 | = -2

411K

det| 2 3 ; 3 3 | = -3

det| 5 6 ; 2 6 | = 18

377K

∂n/∂θ = 3n

299K

ΔS ≥ 0

401K

\frac{4}{6} \sum_{i=1}^{n} i^{2}

420K

e^{i\pi} + 1 = 0

109K