Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-18 12:40Z
∑_{k=1}^{n} k = n(n+1)/2
4y² + 7y + 7 = 0
det| 11 5 ; 0 12 | = 132
411K
∇²t = 0
CH₄ + 2O₂ → CO₂ + 2H₂O
22K
6β² + 2β + 2 = 0
2φ² + 2φ + 5 = 0
det| 9 4 ; 1 10 | = 86
181K
∑_{k=1}^{n} k = n(n+1)/2
80K