Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-17 22:36Z

N₂ + 3H₂ ⇌ 2NH₃

∇ × E = −∂B/∂t

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F = G m₁m₂ / r²

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9ψ² + 4ψ + 2 = 0

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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∇²z = 0

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d/dβ [β^6] = 6β^5

e^{i\pi} + 1 = 0

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e^{i\pi} + 1 = 0

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det| 6 1 ; 4 7 | = 38

e^{i\pi} + 1 = 0

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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det| 2 3 ; 5 3 | = -9

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\binom{n}{k} = \frac{n!}{k!(n-k)!}

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det| 7 4 ; 4 8 | = 40

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\lim_{β\to 0} \frac{\sin β}{β} = 1

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