Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-19 20:17Z

∑_{k=1}^{n} k = n(n+1)/2

∫₀^∞ e^(-t²) dt = √π / 2

451K

9α² + 7α + 5 = 0

264K

det| 8 9 ; 3 9 | = 45

8ψ² + 7ψ + 0 = 0

297K

det| 9 5 ; 1 10 | = 85

252K

C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

∇ × E = −∂B/∂t

48K

d/dt [t^3] = 3t^2

411K

2n² + 4n + 0 = 0

377K

det| 3 7 ; 2 4 | = -2

299K

∇²γ = 0

401K