Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-18 14:59Z
3γ² + 8γ + 4 = 0
∑_{k=1}^{n} k = n(n+1)/2
438K
PV = nRT
∫₀^∞ e^(-ω²) dω = √π / 2
186K
det| 1 9 ; 5 2 | = -43
det| 5 2 ; 3 6 | = 24
448K
ω = 2πf
∑_{k=1}^{n} k = n(n+1)/2
406K
∂n/∂ψ = 6n
∑_{k=1}^{n} k = n(n+1)/2
455K