Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:49Z

11n² + 5n + 4 = 0

∫₀^∞ e^(-t²) dt = √π / 2

460K

det| 5 6 ; 2 6 | = 18

438K

∫₀^∞ e^(-x²) dx = √π / 2

det| 7 4 ; 4 8 | = 40

186K

∇²γ = 0

411K

4φ² + 6φ + 2 = 0

F = G m₁m₂ / r²

448K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

22K

∫₀^∞ e^(-φ²) dφ = √π / 2

7r² + 8r + 5 = 0

459K

∇ × E = −∂B/∂t

406K

∇²ω = 0

d/dα [α^3] = 3α^2

d/dr [r^2] = 2r^1

ΔS ≥ 0