Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:47Z

11n² + 5n + 4 = 0

\lim_{r\to 0} \frac{\sin r}{r} = 1

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∑_{k=1}^{n} k = n(n+1)/2

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∫₀^∞ e^(-x²) dx = √π / 2

6ω² + 4ω + 4 = 0

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F = G m₁m₂ / r²

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4φ² + 6φ + 2 = 0

det| 9 4 ; 1 10 | = 86

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∇²β = 0

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∫₀^∞ e^(-φ²) dφ = √π / 2

PV = nRT

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iħ ∂ψ/∂t = Ĥψ

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∇²ω = 0

\binom{n}{k} = \frac{n!}{k!(n-k)!}

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