Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-19 20:21Z

∑_{k=1}^{n} k = n(n+1)/2

4t² + 3t + 3 = 0

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∇²β = 0

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det| 8 9 ; 3 9 | = 45

λ = h/p

297K

det| 11 5 ; 0 12 | = 132

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C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

3z² + 5z + 1 = 0

48K

\frac{8}{7} \sum_{i=1}^{n} i^{2}

411K

8ψ² + 7ψ + 0 = 0

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iħ ∂ψ/∂t = Ĥψ

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\oint_C \vec{F}\cdot d\vec{r} = 0

401K

10t² + 9t + 5 = 0

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N₂ + 3H₂ ⇌ 2NH₃

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det| 4 7 ; 2 5 | = 6

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