Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-20 04:47Z

∇²n = 0

det| 4 8 ; 3 5 | = -4

273K

det| 1 4 ; 3 2 | = -10

263K

9r² + 4r + 1 = 0

∫₀^∞ e^(-ω²) dω = √π / 2

139K

9θ² + 7θ + 4 = 0

108K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

8ψ² + 7ψ + 0 = 0

333K

d/dt [t^3] = 3t^2

160K

11γ² + 3γ + 6 = 0

\lim_{ω\to 0} \frac{\sin ω}{ω} = 1

439K

∑_{k=1}^{n} k = n(n+1)/2

413K

\lim_{ψ\to 0} \frac{\sin ψ}{ψ} = 1

PV = nRT

297K

∑_{k=1}^{n} k = n(n+1)/2

128K

∇ × E = −∂B/∂t

404K