Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-21 04:41Z

e^{i\pi} + 1 = 0

∑_{k=1}^{n} k = n(n+1)/2

195K

N₂ + 3H₂ ⇌ 2NH₃

262K

N₂ + 3H₂ ⇌ 2NH₃

6r² + 3r + 1 = 0

∫₀^∞ e^(-α²) dα = √π / 2

244K

det| 11 3 ; 1 12 | = 129

∑_{k=1}^{n} k = n(n+1)/2

231K

det| 7 4 ; 4 8 | = 40

26K

ΔS ≥ 0

\binom{n}{k} = \frac{n!}{k!(n-k)!}

209K

∑_{k=1}^{n} k = n(n+1)/2

331K

F = ma

ω = 2πf

∂t/∂z = 9t