Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:57Z

11n² + 5n + 4 = 0

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

460K

8ψ² + 7ψ + 0 = 0

438K

∫₀^∞ e^(-x²) dx = √π / 2

∇²n = 0

186K

7γ² + 8γ + 3 = 0

411K

4φ² + 6φ + 2 = 0

det| 5 6 ; 2 6 | = 18

448K

PV = nRT

22K

∫₀^∞ e^(-φ²) dφ = √π / 2

9ψ² + 7ψ + 3 = 0

459K

N₂ + 3H₂ ⇌ 2NH₃

406K

∇²ω = 0

det| 3 7 ; 2 4 | = -2

181K

iħ ∂ψ/∂t = Ĥψ

80K

d/dr [r^2] = 2r^1

iħ ∂ψ/∂t = Ĥψ

359K

ΔS ≥ 0

8β² + 5β + 0 = 0

det| 12 6 ; 6 13 | = 120