Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 23:35Z

11t² + 8t + 0 = 0

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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N₂ + 3H₂ ⇌ 2NH₃

438K

∂ω/∂β = 7ω

2n² + 4n + 0 = 0

186K

∇ × E = −∂B/∂t

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det| 3 3 ; 7 4 | = -9

CH₄ + 2O₂ → CO₂ + 2H₂O

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d/dt [t^3] = 3t^2

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∫₀^∞ e^(-θ²) dθ = √π / 2

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\lim_{t\to 0} \frac{\sin t}{t} = 1

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8ψ² + 7ψ + 0 = 0

181K

11φ² + 4φ + 0 = 0

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