Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 20:34Z

det| 6 5 ; 4 7 | = 22

8ψ² + 7ψ + 0 = 0

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∑_{k=1}^{n} k = n(n+1)/2

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∇²φ = 0

d/dt [t^3] = 3t^2

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6t² + 6t + 4 = 0

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\frac{9}{2} \sum_{i=1}^{n} i^{2}

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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∇ × E = −∂B/∂t

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∂γ/∂θ = 2γ

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∑_{k=1}^{n} k = n(n+1)/2

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\lim_{β\to 0} \frac{\sin β}{β} = 1

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