Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-20 06:35Z

∑_{k=1}^{n} k = n(n+1)/2

C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

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∑_{k=1}^{n} k = n(n+1)/2

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e^{i\pi} + 1 = 0

\frac{2}{2} \sum_{i=1}^{n} i^{2}

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e^{i\pi} + 1 = 0

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2H₂ + O₂ → 2H₂O

CH₄ + 2O₂ → CO₂ + 2H₂O

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∑_{k=1}^{n} k = n(n+1)/2

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det| 4 8 ; 0 5 | = 20

N₂ + 3H₂ ⇌ 2NH₃

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6x² + 6x + 1 = 0

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det| 4 7 ; 7 5 | = -29

∑_{k=1}^{n} k = n(n+1)/2

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det| 7 4 ; 4 8 | = 40

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10t² + 5t + 2 = 0

det| 1 6 ; 5 2 | = -28

F = ma