Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 16:20Z

10γ² + 4γ + 3 = 0

det| 7 4 ; 4 8 | = 40

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∑_{k=1}^{n} k = n(n+1)/2

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d/dβ [β^11] = 11β^10

C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

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N₂ + 3H₂ ⇌ 2NH₃

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3x² + 4x + 6 = 0

iħ ∂ψ/∂t = Ĥψ

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∫₀^∞ e^(-θ²) dθ = √π / 2

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∑_{k=1}^{n} k = n(n+1)/2

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\lim_{β\to 0} \frac{\sin β}{β} = 1

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∇²ω = 0

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