Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-19 20:17Z

∑_{k=1}^{n} k = n(n+1)/2

∇ × E = −∂B/∂t

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8ψ² + 7ψ + 0 = 0

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det| 8 9 ; 3 9 | = 45

iħ ∂ψ/∂t = Ĥψ

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det| 4 7 ; 2 5 | = 6

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C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

det| 4 8 ; 3 5 | = -4

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\frac{2}{2} \sum_{i=1}^{n} i^{2}

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det| 2 3 ; 3 3 | = -3

e^{i\pi} + 1 = 0

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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PV = nRT

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8θ² + 8θ + 6 = 0

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d/dt [t^3] = 3t^2

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∂y/∂n = 5y

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