Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 21:25Z

10y² + 2y + 6 = 0

E = mc²

460K

∇ × E = −∂B/∂t

438K

∫₀^∞ e^(-t²) dt = √π / 2

N₂ + 3H₂ ⇌ 2NH₃

186K

\oint_C \vec{F}\cdot d\vec{r} = 0

411K

e^{i\pi} + 1 = 0

∑_{k=1}^{n} k = n(n+1)/2

448K

det| 5 6 ; 2 6 | = 18

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

8ψ² + 7ψ + 0 = 0

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2H₂ + O₂ → 2H₂O

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d/dt [t^3] = 3t^2

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