Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:34Z

11n² + 5n + 4 = 0

PV = nRT

460K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

438K

∫₀^∞ e^(-x²) dx = √π / 2

∑_{k=1}^{n} k = n(n+1)/2

186K

d/dt [t^3] = 3t^2

411K

4φ² + 6φ + 2 = 0

∂y/∂n = 5y

448K

e^{i\pi} + 1 = 0

22K

∫₀^∞ e^(-φ²) dφ = √π / 2

det| 9 4 ; 1 10 | = 86

459K

\frac{12}{6} \sum_{i=1}^{n} i^{2}

406K

∇²ω = 0

d/dα [α^3] = 3α^2

d/dr [r^2] = 2r^1

ΔS ≥ 0