Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-18 21:06Z
10y² + 2y + 6 = 0
∑_{k=1}^{n} k = n(n+1)/2
438K
∫₀^∞ e^(-t²) dt = √π / 2
\binom{n}{k} = \frac{n!}{k!(n-k)!}
411K
e^{i\pi} + 1 = 0
\lim_{β\to 0} \frac{\sin β}{β} = 1
448K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
\frac{4}{6} \sum_{i=1}^{n} i^{2}
406K
λ = h/p
∑_{k=1}^{n} k = n(n+1)/2
80K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
455K