Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-19 20:37Z

∑_{k=1}^{n} k = n(n+1)/2

d/dt [t^3] = 3t^2

451K

∑_{k=1}^{n} k = n(n+1)/2

264K

det| 8 9 ; 3 9 | = 45

∇ × E = −∂B/∂t

297K

\lim_{ω\to 0} \frac{\sin ω}{ω} = 1

252K

C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

9θ² + 7θ + 4 = 0

48K

det| 10 2 ; 3 11 | = 104

411K

det| 2 3 ; 3 3 | = -3

N₂ + 3H₂ ⇌ 2NH₃

377K

PV = nRT

299K

iħ ∂ψ/∂t = Ĥψ

401K

8ψ² + 7ψ + 0 = 0

420K

∂α/∂ω = 3α

109K