Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 11:38Z

∇²t = 0

E = mc²

460K

det| 7 4 ; 4 8 | = 40

438K

det| 6 4 ; 3 7 | = 30

det| 4 8 ; 3 5 | = -4

186K

d/dφ [φ^1] = 1φ^0

411K

ΔS ≥ 0

∑_{k=1}^{n} k = n(n+1)/2

448K

\lim_{t\to 0} \frac{\sin t}{t} = 1

22K

1z² + 3z + 2 = 0

N₂ + 3H₂ ⇌ 2NH₃

459K

∑_{k=1}^{n} k = n(n+1)/2

406K

7t² + 3t + 1 = 0