Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-19 03:06Z

∇²x = 0

ω = 2πf

451K

d/dt [t^3] = 3t^2

264K

det| 3 9 ; 1 4 | = 3

det| 3 1 ; 7 4 | = 5

297K

∑_{k=1}^{n} k = n(n+1)/2

252K

CaCO₃ → CaO + CO₂

∑_{k=1}^{n} k = n(n+1)/2

48K

\frac{4}{9} \sum_{i=1}^{n} i^{2}

411K

det| 8 9 ; 4 9 | = 36

E = mc²

377K

11t² + 9t + 7 = 0

299K

det| 7 6 ; 6 8 | = 20

∇ × E = −∂B/∂t

401K

8ψ² + 7ψ + 0 = 0

420K

∑_{k=1}^{n} k = n(n+1)/2

109K

∇ × E = −∂B/∂t

184K