Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-20 04:19Z

∇²n = 0

∇ × E = −∂B/∂t

273K

\binom{n}{k} = \frac{n!}{k!(n-k)!}

263K

9r² + 4r + 1 = 0

8ψ² + 7ψ + 0 = 0

139K

5z² + 8z + 3 = 0

108K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

11t² + 9t + 7 = 0

333K

det| 3 1 ; 7 4 | = 5

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11γ² + 3γ + 6 = 0

E = mc²

439K

d/dt [t^3] = 3t^2

413K

\lim_{ψ\to 0} \frac{\sin ψ}{ψ} = 1

det| 12 6 ; 6 13 | = 120

det| 6 1 ; 3 7 | = 39

e^{i\pi} + 1 = 0

N₂ + 3H₂ ⇌ 2NH₃