Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 16:01Z

10γ² + 4γ + 3 = 0

d/dt [t^3] = 3t^2

460K

∇ × E = −∂B/∂t

438K

d/dβ [β^11] = 11β^10

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

186K

∇²β = 0

411K

3x² + 4x + 6 = 0

\lim_{r\to 0} \frac{\sin r}{r} = 1

448K

11φ² + 4φ + 0 = 0

22K

CaCO₃ → CaO + CO₂

\lim_{ω\to 0} \frac{\sin ω}{ω} = 1

459K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

406K

Fe₂O₃ + 3CO → 2Fe + 3CO₂

8ψ² + 7ψ + 0 = 0

181K

Fe₂O₃ + 3CO → 2Fe + 3CO₂

∑_{k=1}^{n} k = n(n+1)/2

F = ma