Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 21:06Z

10y² + 2y + 6 = 0

∇²β = 0

460K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

438K

∫₀^∞ e^(-t²) dt = √π / 2

Fe₂O₃ + 3CO → 2Fe + 3CO₂

186K

d/dt [t^3] = 3t^2

411K

e^{i\pi} + 1 = 0

3z² + 5z + 1 = 0

448K

2n² + 4n + 0 = 0

22K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

\lim_{r\to 0} \frac{\sin r}{r} = 1

459K

det| 3 6 ; 0 4 | = 12

406K

∇ × E = −∂B/∂t

181K

∇ × E = −∂B/∂t

80K

8ψ² + 7ψ + 0 = 0

359K