Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:57Z

11n² + 5n + 4 = 0

det| 10 2 ; 3 11 | = 104

460K

∑_{k=1}^{n} k = n(n+1)/2

438K

∫₀^∞ e^(-x²) dx = √π / 2

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

186K

e^{i\pi} + 1 = 0

411K

4φ² + 6φ + 2 = 0

λ = h/p

448K

11φ² + 4φ + 0 = 0

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∫₀^∞ e^(-φ²) dφ = √π / 2

\oint_C \vec{F}\cdot d\vec{r} = 0

459K

N₂ + 3H₂ ⇌ 2NH₃

406K

det| 7 4 ; 4 8 | = 40

181K

∂y/∂n = 5y

80K

∂y/∂γ = 8y

359K