Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-17 23:33Z

Fe₂O₃ + 3CO → 2Fe + 3CO₂

\binom{n}{k} = \frac{n!}{k!(n-k)!}

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5z² + 8z + 3 = 0

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\binom{n}{k} = \frac{n!}{k!(n-k)!}

∑_{k=1}^{n} k = n(n+1)/2

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Fe₂O₃ + 3CO → 2Fe + 3CO₂

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ω = 2πf

N₂ + 3H₂ ⇌ 2NH₃

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det| 7 4 ; 4 8 | = 40

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2n² + 4n + 0 = 0

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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